1.

`sin(-11pi)/(3)`

Answer» `sin(-11pi)/(3) = -sin(11pi)/(3)`
`=-sin(2 xx 2pi -pi/3)`
`=-(-sinpi/3) = sinpi/3 = sqrt(3)/2`
Therefore, `sin(-11pi)/(3) = sqrt(3)/2`. Ans.


Discussion

No Comment Found