InterviewSolution
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InterviewSolution
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`sin^(2)6x-sin^(2)4x=sin2xsin10x` |
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Answer» LHS `=sin^(2)6x-sin^(2)4x` `=1/2[2sin^(2)6x-2sin^(2)4x]` `=1/2[(1-cos12x)=(1-cos8x)]` `[therefore 2sin^(2)nx=(1-cos2nx)]` `=1/2[cos8x-cos12x]` `1/2[2sin(8x+12x)/(2) sin(12x-8x)/(2)]` `=sin10xsin2x=sin2xsin10x` =R.H.S. Hence Proved. |
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