Saved Bookmarks
| 1. |
Sin^2x+cos^2x find dy/ dx |
|
Answer» Answer We have sin x+cos 2 y=1 Differentiating both SIDES w.r.t. x, we obtain dx d
(sin 2 x+cos 2 y)= dx d
(1) ⇒2sinx. dx d
(sinx)+2cosy. dx d
(cosy)=0 ⇒2sinxcosx+2cosy(−siny). dx dy
=0 ⇒sin2x−sin2y dx dy
=0 ∴ dx dy
= sin2y sin2x
|
|