sin A = 7/25, find the value of 48 tan A - 21 cot A + 50 cos A.1. 252.

1.	sin A = 7/25, find the value of 48 tan A - 21 cot A + 50 cos A.1. 252. 243. -104. 10
Answer» Correct Answer - Option 3 : -10 Given: sinA= 7/25 Concept used: sinA = P/H tanA = P/B cotA = B/P cosA = B/H Phythagoras theorem H² = P²+ B² Where, P → Perpendicular B → Base H → Hypotenus Calculations: sinA = 7/25 = P/H P = 7 and H = 25 According to phythagoras theorem ⇒ 25² = 7² + B² ⇒ B² = 625 – 49 ⇒ B = √576 = 24 tanA = P/B = 7/24 cotA = 24/7 cosA = 24/25 48 tan A - 21 cot A + 50 cos A. ⇒ 48 × (7/24) – 21 × (24/7) + 50 × (24/25) ⇒ 14 – 72 + 48 ⇒ -10 ∴ The correct answer is -10

sin A = 7/25, find the value of 48 tan A - 21 cot A + 50 cos A.1. 252. 243. -104. 10

Answer» Correct Answer - Option 3 : -10

Given:

sinA= 7/25

Concept used:

sinA = P/H

tanA = P/B

cotA = B/P

cosA = B/H

Phythagoras theorem

H² = P²+ B²

Where,

P → Perpendicular

B → Base

H → Hypotenus

Calculations:

sinA = 7/25 = P/H

P = 7 and H = 25

According to phythagoras theorem

⇒ 25² = 7² + B²

⇒ B² = 625 – 49

⇒ B = √576 = 24

tanA = P/B = 7/24

cotA = 24/7

cosA = 24/25

48 tan A - 21 cot A + 50 cos A.

⇒ 48 × (7/24) – 21 × (24/7) + 50 × (24/25)

⇒ 14 – 72 + 48

⇒ -10

∴ The correct answer is -10