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Sin theta=( a+b)/(a-b) find tan^2 theta |
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Answer» Step-by-step EXPLANATION: sin THETA = (a+b)/(a-b) sin²theta = (a+b)²/(a-b)² 1-cos²theta = sin²theta = (a+b)²/(a-b)² By solving , we GET cos²theta = -4AB/(a-b)² tan²theta = sin²theta/cos²theta = {(a+b)²/(a-b)²}/{-4ab/(a-b)²} = (a+b)²/-4ab = -(a+b)²/4ab |
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