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` ( sin theta tan theta)/( 1- cos theta) = 1 + sec theta` |
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Answer» LHS `(sin^2theta)/costheta*1/(1-costheta)*(1+costheta)/(1+costheta)` `sin^2theta/(costheta(1-cos^2theta))*(1+costheta)` `sin^2theta/sin^2theta*(1+costheta)/costheta` `1+sectheta` RHS. |
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