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`(sin3theta)/(2cos2theta+1)=(1)/(2)` if `(n in Z)`A. `theta = 2n pi+(pi)/(6)`B. `theta=2n pi-(pi)/(6)`C. `theta=n pi+(-1)^(n)(pi)/(6)`D. `theta-n pi-(pi)/(6)` |
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Answer» Correct Answer - C `(sin 3theta)/(2cos 2theta +1)=(1)/(2)` `rArr (3 sin theta - 4 sin^(3)theta)/(3-4 sin^(2)theta)=(1)/(2)` `rArr sin theta =(1)/(2)rArr theta = n pi+(-1)^(n)pi//6, n in Z` |
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