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`sin5A=5cos^4AsinA-10cos^2Asin^3A+sin^5A` |
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Answer» `L.H.S. = sin5A = sin(3A+2A) = sin3Acos2A+sin2Acos3A` `=(3sinA-4sin^3A)(1-2sin^2A)+(4cos^3A-3cosA)(2sinAcosA)` `=3sinA-6sin^3A-4sin^3A+8sin^5A+8cos^4AsinA - 6sinAcos^2A` `=sin^5A+5cos^4AsinA-10cos^2Asin^3A = R.H.S.` |
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