Saved Bookmarks
| 1. |
SinA=1/√2,tanB=1. prove that cos(A+B)=0 |
|
Answer» -STEP EXPLANATION:GIVEN:-sinA=1/√2,tanB=1.To PROVE:-If sinA=1/√2,tanB=1 then prove that cos(A+B)=0Solution:-Given that-SinA=1/√2=>SinA=Sin 45°A=45°------(1)And TanB=1=>TanB=Tan 45°B=45°--------(2)Now LHS:-Cos(A+B)=>Cos(45°+45°)=>Cos90°=>0=RHSLHS=RHSHence Proved. |
|