1.

Since speed changed at a uniform rate and the average velocity is equal to the average of the Initial and final speeds. how far has the particle traveled while It was accelerating ?

Answer»

51 ft
600ft
210ft
less than 20 mi.

SOLUTION :`v=(v_1+v_2)/2`
v=1/2(23+58) mi/hr . V=40.5 mi/hr
v=40.5 x `"5280 ft./min."/"3600 SEC./hr."` =59.41 ft/sec.
X=59.4 ft./sec. x 3.5 sec X =208 ft .


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