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`((sintheta+sinphi)/(costheta+cosphi)+(costheta-cosphi)/(sintheta-sinphi))` का मान बताएं ?A. 1B. 2C. `1//2`D. 0 |
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Answer» Correct Answer - d `((sintheta+sinphi)/(costheta+cosphi)+(costheta-cosphi)/(sin theta-sinphi))` Put `theta=90^(@)` `phi=0^(@)` `therefore((sin90+sin0)/(cos90+cos0)+(cos90-cos0)/(sin90-sin0))` `rArr((1+0)/(0+1)+( 0-1)/(1-0))` |
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