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Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10, 12 minutes respectively. In 30 hours, how many times do they toll together? |
Answer» Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10, 12 minutes respectively. Find LCM using prime factorization: 2 = 2 (prime number) 4 = 2 × 2 6 = 2 × 3 8 = 2 × 2 × 2 10 = 2 × 5 12 = 2 × 2 × 3 Therefore, LCM (2, 4, 6, 8, 10, 12) = 2 x 2 x 2 × 3 × 5 = 120 After every 120 minutes = 2 hours, bells will toll together. So, required number of times = (30/2 + 1) = 16 times. |
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