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Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10, 12 minutes respectively. In 30 hours, how many times do they toll together? |
Answer» Six bells toll together at intervals of 2,4, 6, 8, 10 and 12 minutes, respectively. Prime factorization: 2 = 2 4 = 2 × 2 6 = 2 × 3 8 = 2 × 2 × 2 10 = 2 × 5 12 = 2 × 2 × 3 ∴ LCM (2, 4, 6, 8, 10, 12) = 23 × 3 × 5 = 120 Hence, after every 120minutes (i.e. 2 hours), they will toll together ∴ Required number of times = \((\frac{30}{2}+1)\) = 16 |
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