Six grams of urea ( molar mass = 60 ) are dissolved in 90 g of water. – InterviewSolution

1.	Six grams of urea ( molar mass = 60 ) are dissolved in 90 g of water. The relative lowering of vapour pressure is equal to
Answer» 0.0196 0.06 0.01 0.0202 Solution :Relative LOWERING of VAPOUR pressure `=` Mole fraction of SOLUTE `(x_(B))` `x_(B)=((6)/(60))/(6/60 +90/18)=0.0196`

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