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Sketch the change in flux, emf and force when a conducting rod PQ of resistance R and length L moves freely to and fro between A and C will speed v on a rectangular conductor placed in uniform magnetic field as shown in the figure. |
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Answer» SOLUTION :The flux enclosed by the rod is, `phi=BLx" for "0lexleb=BLb" for "blexle2b` Now, the magnitude of induced EMF is, `e=-(dphi)/(dt)=-BL(dx)/(dt)=-BLv" for "0lexleb` `=-BL(db)/(dt)=0" for "blexle2b` Now, the magnitude of induced current when induced emf is non-zero is, `I=(e)/(R)=(BLv)/(R)` The force required to keep the CONDUCTOR in motion is, `F=BIL=B(BLv)/(R)L=(B^(2)L^(2)v)/(R)` `THEREFORE F=(B^(2)L^(2)v)/(R)" for "0lexleb=0" for "blexle2b`. Therefore, the variation of flux, emf and force are shown in fig 
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