1.

Sketch the variation of electric circle potential on the x-axis with respect to x for x = - oo to x = + oo in the following cases. (a)

Answer»

Solution :(a) Electric potential at `P` :
`V_(p) = (1)/( 4pi in_(0)).[(Q)/(x) + (Q)/(d - x)] = (Q)/(4 pi in_(0)) .(d)/(x(d - x))`
`V_(p)` is minimum if `x(d - x)` is maximum.
`x(d - x)` is maximum if `x = d - x rArr x = d//2`.
At mid -point of `OA` , electric potential is minimum.
At `O : x rarr 0 ,V rarr oo`
At `A : x rarr d , V rarr oo`
From `O` to `A` , electric potential decreases REACHING to minimum VALUE and then increases.
Left of `O` : At DISTANCE `x` from `O`
`V = (1)/( 4 pi in_(0)) [(Q)/(x) + (Q)/(d + x)]`
`x rarr 0 , V rarr oo`
`x rarr -oo , V rarr 0`
Right of `A` : At distance `x` from `O`
`V = (1)/(4pi in_(0)) [(Q)/(x) + (Q)/(x - d)]`
`x rarr d , V rarr oo`
`x rarr oo , V rarr 0`
(B) At mid - point of `OA , V = 0`
`0 lt x lt (d)/(2) , V is + ve`
`(d)/(2) lt x lt d , V is - ve`
`x rarr 0 , V rarr oo`
`x rarr 0 , V rarr oo`
`x rarr -oo , Vrarr 0`
Right of `A : V is -ve`
`x rarr d , V rarr oo`
`x rarr oo , V rarr 0`




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