1.

Slope of the straight line obtained by plotting log_(10)k against 1/T represents what term?

Answer»

`-E_(a)`
`-2.303 E_(a)//R`
`-E_(a)//2.303 R`
`-E_(a)//R`

SOLUTION :`UNDERSET(Y)underset(UARR)(log k) = underset(m) underset(uarr)(E_(a)/(2.303R)) underset(X)underset(DARR)(1/T) + underset(c)underset(uarr)(logA)`
Where m `to` SLOPE


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