1.

Slopes of both the lines are same.] 27. Prove that lines represented by equations.3y - 2x - 4 = 0 and 4y - 6x - 2 = 0 are perpendicular to each other.(Hint. Prove that the slope my x m2 = - 1]​

Answer»

something wrong in the questionStep-by-step explanation:Given lines are 3y - 2x - 4 = 0 and 4y - 6x - 2 = 0=> let 2x - 3y + 4 = 0 ----------(1)and 6x - 4y + 2 = 0 -----------(2)slope of LINE (1) is M1 = -a/b = -2/-3 = 2/3slope of line (2) is m2 = -a/b = -6/-4 = 3/2product of the slopes = m1 x m2= 2/3 x 3/2 = 1If m1 x m2 = -1 , then the lines are SAID to be perpendicular to each other .



Discussion

No Comment Found

Related InterviewSolutions