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Small spherical ball of silver metal used in jewellery having diameter 0.1 cm, which is obtained by the electrolytic deposition.It total number of balls in jewellery is 10,000, then calculate the applied amount of electricity in coulombs, which is used on the deposition on electrodes having entire surface 0.12 m^2.[Density of Ag = 10.5] It is assumed that 3.5% electricity consumed as wastage during electrolysis and 60% of electrode body immersed in electrolyte.[Give your answer in multiple of 10^4] |
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Answer» Surface area of electrodes =`0.12 m^2=1200 cm^2` Weight of jewellery =`4/3 pir^3xx10,000xx"DENSITY"=4/3xx3.14xx(0.05)^3xx10000xx10.5=54.9` GRAM Now amount of electricity in faraday =`("wt. of Ag")/("EQUIVALENT wt. of Ag")=54.9/108=0.50 F = 48250` coulomb So applied electricity amount =`(48250xx100)/96.5` =50,000 coulomb =`5xx10^4` coulomb |
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