1.

समीकरण `cos^(2)theta=((x+y)^(2))/(4xy)` तभी संभव है?A. `x=-y`B. `x gt y`C. `x=y`D. `x lt y`

Answer» Correct Answer - c
`cos^(2)theta=((x+y)^(2))/(4xy)`
max. value of `cos^(2)theta=1`
`rArrf1=((x+y)^(2))/(4xy)`
`rArr4xy=(x+y)^(2)`
`rArr4xy=x^(2)+y ^(2)2xy`
`rArr0=x^(2)+y^(2)-2xy`
`rArr0=(x-y)^(2)`
`rArr0=x-yrArrx=y`


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