SN I reaction undergoes through a carbocation intermediate as follows : R−X(aq.)Slow⇌R∗(aq.)+X−(aq.)H2O−−→fastROH(aq.)+H+(aq.) [R = t-Bu, iso-Pr, Et, Me] (X = Cl, Br, I) The correct statements are (I) The decreasing order of rate of SN 1 reaction is t-BuX > iso-PrX > EtX > MeX (II) The decreasing order of ionization energy is MeX > EtX > iso-PrX> t-BuX (III) The decreasing order of energy of activation is t-BuX > iso-PrX > EtX > MeX

SN I reaction undergoes through a carbocation intermediate as follows

1.	SN I reaction undergoes through a carbocation intermediate as follows : R−X(aq.)Slow⇌R∗(aq.)+X−(aq.)H2O−−→fastROH(aq.)+H+(aq.) [R = t-Bu, iso-Pr, Et, Me] (X = Cl, Br, I) The correct statements are (I) The decreasing order of rate of SN 1 reaction is t-BuX > iso-PrX > EtX > MeX (II) The decreasing order of ionization energy is MeX > EtX > iso-PrX> t-BuX (III) The decreasing order of energy of activation is t-BuX > iso-PrX > EtX > MeX
Answer» $S_{N}$ I reaction undergoes through a carbocation intermediate as follows : $R - X (a q .) S l o w ⇌ R * (a q .) + X^{-} (a q .) H_{2} O - - \to f a s t R O H (a q .) + H^{+} (a q .)$ [R = t-Bu, iso-Pr, Et, Me] (X = Cl, Br, I) The correct statements are (I) The decreasing order of rate of S_N 1 reaction is t-BuX > iso-PrX > EtX > MeX (II) The decreasing order of ionization energy is MeX > EtX > iso-PrX> t-BuX (III) The decreasing order of energy of activation is t-BuX > iso-PrX > EtX > MeX