1.

Sneha gave candy to a group of children. Ifshe gave 5 candies to each child, sheneeded another 2 candies. If she gave eachchild 4 candie, there were 3 candies left.How many children were there? How manycandies did Sneha have? Please explain this question.​

Answer»

\large\underline\purple{\bold{Solution :-  }}

☆ Let number of candies be x.

☆Let number of children be y.

☆ According to statement, If she GAVE 5 candies to each child, she needed another 2 candies.

\longrightarrow \:   \boxed{ \red{\tt \: x \:  = 5y - 2}} -  - (i)

☆ According to next CONDITION, If she gave each

child 4 candies, there were 3 candies left.

\longrightarrow \: \boxed{ \pink { \tt \: x = 4y + 3}} -  - (ii)

☆ On equating (i) and (ii), we getc

\longrightarrow \:  \tt \: 5y - 2 = 4y + 3 \\  \\ \longrightarrow \:  \tt \: 5y - 4y = 3 + 2

\tt\implies \: \boxed{ \purple{ \tt \: y \:  =  \: 5}}

☆ On substituting value of y in equation (i), we GET

\longrightarrow \:  \tt \: x \:  = 5 \times 5 - 2

\tt\implies \: \boxed{ \pink{ \tt \: x \:  =  \: 23}}

\boxed{\begin{gathered}\begin{gathered}\bf Hence \:  -  \:  \begin{cases} &\sf{number \: of \: children \:  = \:  5} \\ &\sf{number \: of \: candies \:  =  \: 23} \end{cases}\end{gathered}\end{gathered}}



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