1.

SO_2Cl_2 to SO_2 +Cl_2 is a first order gas reaction with k = 2.2 xx 10^(-5) sec^(-1)" at " 320^@C Percentage of SO_2Cl_2 decomposed on heating for 90 minutes is

Answer»

0.0887
0.887
0.0113
0.113

Solution :`k = 2.303/tlog.(a)/ (a-x)or log.([A])_0/[A]_t= (KT)/2.303`
`=(2.2 xx 10^(-5)xx 60 xx 90)/2.303 = 0.0516`
Hence, `[A]_0/[A]_t=AL(0.0516) = 1.127`
`or [A]_t/[A]_0= 1/1.127=0.887`
AMOUNT decomposed `=1-[A]_t/[A]_0`
`=1-0.887 = 0.113`
% Amount decomposed = 11.3%


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