1.

soap bubble in vacuum has a radius of 3 cm and another soap bubble in vacuum has a radius of 4 cetwo bubbles coalesce under isothermal conditions then the radius of the new bubble is(A) 3.3 cm(C) 5 cm(D) 7 cm(B) 4.5 cm

Answer»

Excess pressure inside a soap bubble:

P=4TR

Here,Tis surface tension andRis radius of the bubble.

Volume of soap bubble:

V=43πR3

Under isothermal conditions:

PV=P1V1+P2V2(4TR)(43πR3)=(4Tr1)(43πr13)+(4Tr2)(43πr23)R2=r12+r22R=r1^2+r2^2√=(3)^2+(4)^2√=5cm



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