1.

Sodium and copper have work functions of 2.3 eV and 4.6 eV respectively. The ratio of their threshold wavelengths is

Answer»

`1:2`
`2:1`
`1:4`
`4:1`

SOLUTION :Since `phi_(0)=(hc)/(lamda_(0))`, HENCE `=((lamda_(0))_(Na))/((lamda_(0))_(Cu))=((phi_(0))_(Cu))/((phi_(0))_(Na))=(4.6)/(2.3)=2:1`.


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