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Sol e the question present in the image and please explain in detail... WRONG ANSWER WILL BE REPORTED INSTANTLY!!!! |
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Answer» tan⁶ x = 1 + 3 sec² x.tan² xLHS= sec⁶ x−tan⁶ x = (sec² x)³ − (tan² x)³ = {sec² x − tan² x}³ + 3sec² x . tan² x(sec² x−tan² x)= 1 + 3 sec² x.tan² x [ SINCE sec² x − tan² x=1]= RHSHOPE IT HELPS U.. |
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