1.

Solid Ba(NO_(3))_(2) is gradually dissolved in a 1.0xx10^(-4)M Na_(2)CO_(3) solution. At what concentration of Ba^(2+) will a precipitate begin to form ? (K_(sp) " for for " BaCO_(3)=5.1xx10^(-9))

Answer»

`5.1xx10^(-5)M`
`8.1xx10^(-8)M`
`8.1xx10^(-7)M`
`4.1xx10^(-5)M`

Solution :`underset(1xx10^(-4)M)(Na_(2)CO_(3)) to underset(1xx10^(-4)M)(2NA^(+))+ underset(1xx 10^(-4)M)(CO_(3)^(2-))`
`K_(sp(BaCO_(3)))=[Ba^(2+)][CO_(3)^(2-)]`
`[Ba^(2+)]=(5.1xx10^(-9))/(1xx10^(-4))=5.1xx10^(-5)M`


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