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Solubility of `AgCl` at `20^(@)C` is `1.435xx10^(-3) g per litre`. The solubility product of `AgCl` isA. `1xx10^(-5)`B. `1xx10^(-10)`C. `1.435xx10^(-5)`D. `108xx10^(-3)` |
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Answer» Correct Answer - B `S=1.435xx10^(-3)g//l`, `=(1.435xx10^(-3))/(143.5)=10^(-5)M` `K_(sp)=SxxS=10^(-10)` `(S^(2))=10^(-10)` |
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