1.

Solubility of `AgCl` at `20^(@)C` is `1.435xx10^(-3) g per litre`. The solubility product of `AgCl` isA. `1xx10^(-5)`B. `1xx10^(-10)`C. `1.435xx10^(-5)`D. `108xx10^(-3)`

Answer» Correct Answer - B
`S=1.435xx10^(-3)g//l`, `=(1.435xx10^(-3))/(143.5)=10^(-5)M`
`K_(sp)=SxxS=10^(-10)`
`(S^(2))=10^(-10)`


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