`10 mL` of `10^(-6) M HCl` solution is mixed with `90mL H_(2)O`. `pH` will change approximately:A. By one unitB. By `0.3` unitC. By `0.7` unitD. By `0.1` unit

`10 mL` of `10^(-6) M HCl` solution is mixed with `90mL H_(2)O`. `pH`

1.	`10 mL` of `10^(-6) M HCl` solution is mixed with `90mL H_(2)O`. `pH` will change approximately:A. By one unitB. By `0.3` unitC. By `0.7` unitD. By `0.1` unit
Answer» Correct Answer - C `pH` of `10^(-6) M HCl=6` on dilution `[HCl]=(10^(-6)xx10)/(100)=10^(-7)` Thus new `pH` of `HCl` is not `7` because it is acid. `pH` new solution: `[H^(+)]=10^(-7)+10^(-7)` (from`H_(2)O`) `=2xx10^(-7)` `:. pH=6.7` (approximately)

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`10 mL` of `10^(-6) M HCl` solution is mixed with `90mL H_(2)O`. `pH` will change approximately:A. By one unitB. By `0.3` unitC. By `0.7` unitD. By `0.1` unit

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