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If an aqueous solution at `25^(@)C` has twice as many `OH^(-)` as pure water its `pOH` will beA. `6.699`B. `7.307`C. `7`D. `6.98` |
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Answer» Correct Answer - A `[OH^(-)]=2xx10^(-7)` `pOH=14-pH or-log[OH^(-)]` |
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