1.

Solubility of MX_(2) type electrolyte is 0.5 xx 10^(-4) mole/litre. The value of K_(sp) of the electrolyte is

Answer»

`5 XX 10^(-13)`
`25 xx 10^(-10)`
`1.25 xx 10^(-13)`
`5 xx 10^(12)`

SOLUTION :`MX_(2) hArr underset((S))(M^(2+)) + underset((2S)^(2))(2X^(-))`
`4S^(3) = 4 xx (0.5 xx 10^(-4))^(3) = 5 xx 10^(-13)`.


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