1.

Solubility of PbI_(2) is 0.005 M. Then, the solubility product of PbI_(2) is

Answer»

`6.8 xx 10^(-6)`
`6.8 xx 10^(6)`
`2.2 xx 10^(-9)`
None of these

Solution :`PbI_(2) hArr Pb + I_(2)`.
`K_(sp) = 4S^(3) = 4 xx (0.005) xx (0.005) xx (0.005)`
`K_(sp) = 4 xx 5 xx 5 xx 5 xx 10^(-9)`
`K_(sp) = 500 xx 10^(-9)`
`K_(sp) = 5.0 xx 10^(-7)`.


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