1.

Solubility produce of Ag_2CrO_4 is 1 times 10^-12. What is the solubility of Ag_2CrO_4 in 0.01 M AgNO_3 solution?

Answer»

Solution :Solubility product of `Ag_2CrO_4`
`K_(SP)=1 times 10^-12`
`Ag_2CrO_4 leftrightarrow 2Ag^(+)+CrO_4^(-2)`
`AgNO_3 leftrightarrow Ag^(+) + NO_3^(-)`
`K_(sp)=[Ag^+]^2 [CrO_4^(2-)]`
`[Ag^+]=2s+0.01`
`because 0.01 gt gt 2s`
`therefore [Ag^+]=0.01 M`
`[CrO_4^(2-)]=s`
`K_(sp)=(0.01)^2. (s)`
`1 times 10^-12=(0.01)^2.(s)`
`s=(1 times10^-12)/(10^-2)^2=(1 times10^-12)/10^-4=1 times10^-8 M`


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