1.

Solubility product of a sulphide MS is 3 xx 10^(-25) and that of another sulphide NS is 4 xx 10^(-40). In ammoniacal solution

Answer»

Only NS gets precipitated
Only MS gets precipitated
No sulphide precipitates
Both sulphides precipitate

Solution :The concentration of `S^(2-)` IONS in group IV is lowered by MAINTAINING acidic medium in the presence of `NH_(4)Cl`. The ionization of `H_(2)S` is supressed due t common ION effect. So the ionic product is less than SOLUBILITY product.


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