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Solubility product of Ag_2CrO_4 is 1xx10^(-12) What is the solubility of Ag_2 CrO_4 in 0.01 M AgNO_3 solution?

Answer»

SOLUTION :Given that `K_(sp)=1XX10^(-12)`
`Ag_2 CrO_4(s) hArr 2ag_((aq))^(+)+CrO_((aq))^(-2)`
`underset(0.01M)(AgNO_(3(s))) hArr underset(0.01M)(Ag_((aq))^(+))+underset(0.01M)(NO_(3(aq))^(-))`
`K_(ap)=[AG^+]^2[CrO_(4)^(2-)]""{:[([Ag^+]=2s+0.01),(""0.01gtgt2s),(therefore[Ag^+]=0.01M),([CrO_(4)^(2-)]=s)]:}`
`1xx10^-12=(0.01)^2(s)`
`(s)=(1xx10^(-12))/((10^(-2)^2)=1xx10^-8 M`


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