1.

Solubility product of AgI at 25^@C is 4xx10^(-18)"mole"^2 //L^2 ​. The solubility of AgI in presence of 2xx10^(-4) M Kl solution at 25^@Cis approximately equal to : (in mol/L)

Answer»

`8xx10^(-8)`
`2XX10^(-16)`
`2xx10^(-14)`
`0.5xx10^(-12)`

Solution :`K_"sp"=[Ag^+][I^-]`
`4xx10^(-18)=[Ag^+]xx2xx10^(-4)`
`[Ag^+] = 2 XX 10^(-14)` M


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