1.

Solubility product of BaCl_(2) is 4 xx 10^(-9). Its solubility in moles/litre would be

Answer»

`1 XX 10^(-3)`
`1 xx 10^(-9)`
`4 xx 10^(-27)`
`1 xx 10^(-27)`

Solution :`K_(sp) = 4S^(3), S^(3) = (4 xx 10^(-9))/(4) = 10^(-9)`
`:. S = 10^(-3) M`.


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