1.

Solubility (s) of CaF_(2) in terms of its solubility product is given as

Answer»

`s = (K_(sp))^(1//3)`
`s = (K_(sp)//2)^(1//3)`
`s = (K_(sp)//4)^(1//3)`
`s = (K_(sp)//2)^(1//2)`

SOLUTION :It is TERNARY electrolyte,
`CaF_(2) harr Ca^(2+) + 2F^(-)`
Let solubility of `CaF_(2)` be s mol `"litre"^(-1)`
Then `{:(CaF_(2) hArr,Ca^(2+),+,2F^(-)),(,s,,2s):}`
Let `K_(sp) = [Ca^(2+)] [F^(-)]^(2) = (s) xx (2s)^(2) = 4S^(3)`
`s = sqrt((K_(sp))/(4))`.


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