1.

Solution of ZnS in dil HCl , when treated with NaOH solution , a white ppt.is formed which dissolves in excess of NaOH due to the formation of :

Answer»

`ZN(OH)_2`
`Zn(OH)Cl`
`Na_2ZnO_2`
`Na_2ZnO_3`.

Solution :`ZnS + 2HCL to ZnCl_2 + H_2S `
`ZnCl_2 + 2NaOH to Zn(OH)_2 + 2NaCl`
`Zn(OH)_2 + underset("EXCESS")(2NaOH) to underset("Sod zincate (soluble)")+ 2H_2O`


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