InterviewSolution
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Solution set of `(5x-1)lt (x+1)^(2)lt (7x -3)` isA. (1, 4)B. [2, 4]C. (2, 4)D. `(-oo, 1)cup(2, oo)` |
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Answer» Correct Answer - C We have, `(5x-1) lt (x+1)^(2) lt (7x-3)` `rArr 5x-1 lt (x+1)^(2) " and " (x+1)^(2) lt (7x-3)` `rArr (x+1)^(2)-(5x-1) gt 0 " and " (x+1)^(2) - (7x -3) lt 0` `rArr x^(2) - 3x + 2 gt 0 " and " x^(2) - 5x + 4 lt 0` `rArr (x-1)(x-2) gt o " and " (x-1) (x-4) lt 0` `rArr x in (-oo, 1)cup(2, oo) " and " x in (1, 4)` `rArr x in (2, 4)` |
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