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Answer» I'm having one file start another file with check parameters to prevent the second file from being opened with out running the first but EVEN when i run the the first the second still comes up withe the same error message the start command
Code: [Select]start test2.bat %CD% %key1% 1234 %key2% 5678 %key3% 9012 %key4% 3456 i like cheese check code
Code: [Select]IF not "%3"=="1234" goto error1 IF not "%5"=="5678" goto error1 IF not "%7"=="9012" goto error1 IF not "%9"=="3456" goto error1 IF not "%10"=="1" goto error1 IF not "%11"=="like" goto error1 IF not "%12"=="cheese" goto error1 In test2.bat:
test2.bat=%0 %cd%=%1 %key1%=%2 1234=%3 %key2%=%4 5678=%5 %key3%=%6 9012=%7 3456=%8 i=%9 ----- like=%10 cheese=%11
I don't know if anything below ----- can actually work.i guess i have to get rid of i like cheese Well, you can always see if it works.You can only use SINGLE digits for passed parameters and %0 is reserved so you just have %1 to %9 to play with. But you have the SHIFT command.
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