InterviewSolution
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InterviewSolution
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Solve : `1+2cosec x=-("sec"^(2)(x)/(2))/(2)` |
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Answer» Correct Answer - `x=2n pi-(pi)/(2), n in Z` `1+2 cosec x =-("sec"^(2)(x)/(2))/(2)` `rArr 1+2((1+"tan"^(2)(x)/(2))/(2tan.(x)/(2)))=-((1+"tan"^(2)(x)/(2)))/(2)` `rArr 2tan.(x)/(2)+2+2"tan"^(2)(x)/(2)+tan.(x)/(2)+"tan"^(3)(x)/(2)=0` `rArr "tan"^(3)(x)/(2)+2"tan"^(2)(x)/(2)+3tan.(x)/(2)+2=0` `rArr (tan.(x)/(2)+1)("tan"^(2)(x)/(2)+tan.(x)/(2)+2)=0` `tan.((x)/(2))+1=0` `rArr tan.(x)/(2)=tan(-(pi)/(4))` `rArr x = 2n pi-(pi)/(2), n in Z` |
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