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Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π |
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Answer» Here, 2 tan2 x + sec2 x = 2 which gives tan x = ±1/√3 If we take tan x = 1/√3, then x = π/6 or 7π/6 Again, if we take tan x = -1/√3, then x = 5π/6 or 11π/6 Therefore, the possible solutions of above equations are x = 5π/6, 11π/6, 5π/6 and 11π/6 where 0 ≤ x ≤ 2π |
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