1.

Solve 2 tan2x + sec2x = 2 for 0 ≤ x ≤ 2π

Answer»

Here,

2 tan2 x + sec2 x = 2

which gives tan x = ±1/√3

If we take  tan x = 1/√3, then

x = π/6 or 7π/6

Again, if we take  tan x = -1/√3, then

x = 5π/6 or 11π/6

Therefore, the possible solutions of above equations are

x = 5π/6, 11π/6, 5π/6 and 11π/6 

where 0 ≤ x ≤ 2π



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