Solve 2x-3=√2x2-2x +21

1.	Solve 2x-3=√2x2-2x +21
Answer» Step-by-step EXPLANATION: Given equation is $2x - 3 = \sqrt{2} {x}^{2} - 2x + 21$ $\sqrt{2} {x}^{2} - 2x - 2x + 21 + 3 = 0$ $\sqrt{2} {x}^{2} - 4x + 24 = 0$ To find the roots we are USING the below formula: $x = (- b + \sqrt{ {b}^{2} - 4ac} ) \div 2a$ $x = (- b - \sqrt{ {b}^{2} - 4ac} ) \div 2a$ Here $b = - 4$ $a = \sqrt{2}$ $c = 24$ We have to SUBSTITUTE these values in above formula ,then we get the roots of above equation

Answer»

Step-by-step EXPLANATION:

Given equation is

$2x - 3 = \sqrt{2} {x}^{2} - 2x + 21$