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Solve `3tan^(2) theta-2 sin theta=0`. |
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Answer» Correct Answer - `theta=n pi, n pi +(-1)^(n) pi/6, n in Z` `tan^(2) theta-2 sin theta=0` or `3(sin^(2) theta)/(cos^(2) theta)-2 sin theta=0, cos theta ne 0` or `3 sin^(2) theta-2 sin theta (1- sin^(2) theta)=0` or `3 sin^(2) theta-2 sin theta (1- sin^(2) theta)=0` or `sin theta (2 sin^(2) theta+3 sin theta -2)=0` or `sin theta (2 sin theta-1) (sin theta+2)=0` or `sin theta=0, 1-2` (rejected) `rArr theta=npi, n pi +(-1)^(n) pi/6, n in Z` |
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