Solve: `3tan(theta-15^(@))=tan(theta+15^(@))`

1.	Solve: `3tan(theta-15^(@))=tan(theta+15^(@))`
Answer» `3tan(theta-15^(@))=tan(theta+15^(@))` `rArr 3sin(theta-15^(@))/(cos(theta-15^(@)))=(sin(theta +15^(@))cos(theta-15^(@))` `rArr 3.{2cos(theta+15^(@))sin(theta-15^(@))}=2sin(theta+15^(@)).cos(theta-15^(@))` `rAr 3(sin2theta-sin30^(@))=sin2theta+sin30^(@)` `=4 xx 1/2` `rArr sin2theta=1` `=sinpi/2` `therefore 2theta=npi+(-1)^(n)pi/2` `rArr theta=(npi)/(2)+(-1)^(n)pi/4` Ans.

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