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Solve a problmedifferingfrom theforgoing one by a magneticfield with inductionB = 0.8 Treplacingthe electricfield. |
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Answer» Solution :CHOICE `vec(B)` in the `Z` direction, andthe velocity `vec(v) = (sin alpha, 0, v cos alpha)` in the`x-z` plane, then in the `K'` FRAME, `{:(vec(E')_(||)=vec(E)_(||)=0),(vec(E')_(bot)=(vec(v)xxvec(B))/(sqrt(1-v^(2)//c^(2)))):}:|{:(VECB'_(||)=vec(B)_(||)),(vec(B')_(bot)=(vec(B)_(bot))/(sqrt(1-v^(2)//c^(2)))):}` We findsimilarly, `E' = (c BETA B sinalpha)/(sqrt(1 - beta^(2)))` `B' = B sqrt((1 - beta^(2) cos^(2) alpha)/(1 - beta^(2))) tan alpha' = (tan alpha)/(sqrt(1 - beta^(2)))` |
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