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Solve : Batch loop (Resolved) oops - error fix? |
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Answer» Using the Command Prompt in Win XP. Date format is Day mm/dd/yyyy just out of curiosity, how did you work out the '%date:~4,2%. I mean, I know %date% shows the full date so how did you get the ':~4,2' in the line below? I'm definitely not the best one to explain that but in my understanding Date environment variable is stored as an 12-byte FIELD in the format such as Sun 11112007 and is obviously updated automatically when the clock goes past midnight. So %date=:~4,2% skips the first 4 bytes (Sun + space) and returns the next two bytes. i.e. 11 To select the year one would use %date=:~8,4% i.e. skip 8 bytes and return the next 4 making it 2007. (Or %date:~-4% would give the same result). Some instructions are here. I hope I've not made a fool of myself with the above explanation, my technical knowledge is not all that good. Thanks for the 12 IF lines, I already use that solution but looking for something a bit more sophisticated!! I don't understand your explanation that well. But it's not you, it's me, My technical knowledge is very advanced but I haven't got around to learning the 'Bits and Bytes' of Computers. Sorry I couldn't help much. Thanks for explaining. The completed file to display day, date, month and year using a For loop to give the month a name is shown below for anyone interested. The For loop was described on another forum.. Code: [Select]@echo off cls set dateday=%date:~0,3% set datemonth=%date:~4,2% set datenum=%date:~7,2% set dateyear=%date:~10,4% FOR /F "TOKENS=%datemonth%" %%a IN ( "JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC") DO ( set month=%%a) echo. echo. echo Day = %dateday% Date = %datenum% Month = %month% Year = %dateyear% Quote The For loop was described on another forum.. Can you give me the link to the post it was discussed in, please? Oh and I understand your explanation now... Never say sleeping over something won't work.Further testing has shown that an error occurs when datemonth is greater than 07 and the leading digit is 0 (AUG & SEP) so the set datemonth line should read: set/a datemonth=1%date:~4,2%-100 Apologies all round - testing continues. What does the '-100' do?Quote set/a datemonth=1%date:~4,2%-100Quote What does the '-100' do? Oh dear - bear with me on this one. It's not just the -100 which must be considered. You'll see that the original set is now set/a and there is a 1 prior to %date:~..... When Set/a detects a number beginning with 0 it uses the Octal (base eight) system. When considering August and September the month numbers 08 and 09 are invalid so Set fails. Set/a allows arithmetic calculations to be done. The 1 prior to %date:~... means that 1 is to be prefixed to the environment variable %datemonth%. When the month is August (08) %datemonth% would be set to 108. Then the arithmetic CALCULATION -100 is carried out and %datemonth% now becomes 8. I understand that without the leading 0 Set now defaults to the Decimal system (base ten). Cool, This is quite a good script, I would have never thought of it myself. |
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