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Solve : Capture a part of the file name, how can i do it ??

Answer»

eg . I have a file call "200907.txt" , I need to CAPTURE a part of the file NAME "07" to the other file.
How can I do it??

Many Many Thanks~dont understand what ur askingit has a file call '200907.txt'. then i want only capture the 5th and 6th letter (07) of thr file name as parameter ? How can i capture it ?
Really thanks TYPE set /? on your command prompt, read on and you will find the solution..
thanks for your reply
but i require to capture the part of the file name as a VARIABLE.
such as a file name call 200708.txt and i only need the 5th and the 6th letter

but anyway thanks a lot i have already told you where to look...just takes a few minutes to read through set /?
QUOTE

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The /P switch allows you to set the value of a variable to a line of input
entered by the user. Displays the specified promptString before reading
the line of input. The promptString can be empty.
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May also specify substrings for an expansion.

%PATH:~10,5%
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Yes, cityjack, ghostdog74 already told you where to look.


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