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Solve `cos x + cos 2x+...+ cos (nx) =n, n in N`. |
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Answer» Correct Answer - `x=0` We have `cos x + cos 2x +...+ cos (nx) =n` Now, `cosx+cos 2x+...+ cos (nx) le n` So, `cos x = cos 2x = ... = cos nx=1` `:. x=0` |
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